(2x+3)(2x^2-5x+3)=0

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Solution for (2x+3)(2x^2-5x+3)=0 equation:


Simplifying
(2x + 3)(2x2 + -5x + 3) = 0

Reorder the terms:
(3 + 2x)(2x2 + -5x + 3) = 0

Reorder the terms:
(3 + 2x)(3 + -5x + 2x2) = 0

Multiply (3 + 2x) * (3 + -5x + 2x2)
(3(3 + -5x + 2x2) + 2x * (3 + -5x + 2x2)) = 0
((3 * 3 + -5x * 3 + 2x2 * 3) + 2x * (3 + -5x + 2x2)) = 0
((9 + -15x + 6x2) + 2x * (3 + -5x + 2x2)) = 0
(9 + -15x + 6x2 + (3 * 2x + -5x * 2x + 2x2 * 2x)) = 0
(9 + -15x + 6x2 + (6x + -10x2 + 4x3)) = 0

Reorder the terms:
(9 + -15x + 6x + 6x2 + -10x2 + 4x3) = 0

Combine like terms: -15x + 6x = -9x
(9 + -9x + 6x2 + -10x2 + 4x3) = 0

Combine like terms: 6x2 + -10x2 = -4x2
(9 + -9x + -4x2 + 4x3) = 0

Solving
9 + -9x + -4x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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